Question

the sum of 5 consecutive integers is 1000.Find the number​

Answer 1

Answer:

n = 202

Step-by-step explanation:

We can write this as an equation

n + (n-1) + (n-2) + (n-3) + (n-4) = 1000

We simplify to get

n + n - 1 + n - 2 + n - 3 + n - 4 = 1000

Combining like terms gives us

5n - 10 = 1000

Which is further simplified into

5n = 1010

Dividing each side by 5 gives us

n = 202

To double check, we can add this and the other numbers together to get

202 + 201 + 200 + 199 + 198

Which is 1000!

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Answer 2

Answer:

Step-by-step explanation:

let 1st no be =x

then :-   2nd= x+1

           3rd=x+2

            4th=x+3

             5th=x+4

[x]+[x+1]+[x+2]+[x+3]+[x+4] = 1000

5x+10=1000

5x = 1000-10=990                        consecutive means    -लगातार

x=990/5 =118

x=118

put the value in the equations and you will get  the nos.

as     118 , 119 , 120 , 121 , 122