Question

The sum of 5 consecutive integers is 110 find the integers

Answer 1

Answer:

20,21,22,23,24.

Step-by-step explanation:

let the numbers be x,x+1,x+2,x+3,x+4

sum of that consecutive numbers=110

So,x+x+1+x+2+x+3+x+4=110

5x+10=110

5(x+2)=110

x+2=110/5

x+2=22

x=20

Hence,the consecutive numbers are 20,21,22,23,24.

Answer 2

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Consecutive integer :-

• The numbers following order of each other & having a difference of 1 & having its mean and the median equal.

Given :-

The sum of 5 consecutive integers is 110.

To Find :-

The 5 consecutive integers.

Solution :-

Let 5 consecutive no. be x , x+1, x+2 ,x+3, x+4.

x + (x+1) + (x+2) + (x+3) + (x+4) = 110

5x + 6 + 4 = 110

5x + 10 = 110

5x = 110 - 10

5x = 100

x = 100/5

x = 20

The consecutive integers :-

x = 20

(x+1) = 20 +1 = 21

(x+2) = 20 + 2 = 22

(x+3) = 20 + 3 = 23

(x+4) = 20 + 4 = 24

Hence, the the integers are 20 , 21 , 22, 23, 24 .

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