Question

The sum of 5 consecutive integers is 110. What is the fourth number in this sequence?

Answer 1

Let 5 consecutive no. be
n, n+1,n+2,n+3,n+4
n+n+1+n+2+n+3+n+4=110
5n+10=110
5n=110-10
5n=100
n=100/5
n=20
4th term is n+3=20+3=23

Answer 2

let the numbers be x,x+1,x+2,x+3,x+4

summation of numbers is 110

➡️x+x+1+x+2+x+3+x+4=110
5x+10=110
x+2=22
x=20

the fourth digit is x+3=20+3
=23

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