The sum of 5 consecutive integers is 110. What is the fourth number I’m this sequence
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the answer is 20,21,22,23,24
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Let 5 consecutive no. be
n, n+1,n+2,n+3,n+4
n+n+1+n+2+n+3+n+4=110
5n+10=110
5n=110-10
5n=100
n=100/5
n=20
4th term is n+3=20+3=23
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