Question

The sum of 5 consecutive integers is 120. what is the third number in the sequence

Answer 1

Answer:

Step-by-step explanation:

Suppose x is a initial no. of that sequence:

So five consecutive integers are:

x, x+1, x+2, x+3, x+4

Sum of that numbers = 120;

x+x+1+x+2+x+3+x+4 = 120

5x + 10 = 120;

5x = 120 - 10;

5x = 110;

x = 110/5 = 22;

Third number is x+2 = 22+2 = 24;

Answer 2

Answer:

$Let the smallest number be x$

$other numbers are (x + 1), ( x + 2), (x + 3) and (x + 4)\\x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 120\\x + x + 1 + x + 2 + x + 3 + x + 4 = 120$

$5x + 10 = 120\\5x = 110\\x = 22\\first number = x = 22\\second number = x + 1 = 23\\Third  number = x + 2 = 24\\fourth  number = x + 3 = 25\\Fifth number = x + 4 = 26$

The third number is 24

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@GauravSaxena01