The sum of 5 consecutive integers is 35. how many of the five consecutive integers are prime numbers
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Answer:
Step-by-step explanation:
Let the consecutive integers be.
x+x+1+x+2+x+3+x+4=35
5x+10=35
5x=35-10
5x=25
x=25/5
x=5.
The consecutive integers are.
x=5, x+1=6,x+2=7,x+3=8,x+4=9.
In this 5 and 7 are prime numbers.
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To find : five consecutive integers and how many of the five consecutive integers are prime numbers .
Given : The sum of consecutive integers is .
Solution :
- As per given data we know that the sum of consecutive integers is .
- We know that consecutive integers differ by .
- Therefore , let be the consecutive integers.
- According to given condition we write as ,
- Using transposition method we find the value of , by leaving variable at LHS and transposing constants at RHS .
- Now , consecutive numbers are :
- Prime numbers are the numbers having only two factors and number itself .
- Now , prime numbers among obtained consecutive numbers are : and .
Hence , five consecutive integers are .There are two consecutive integers that are prime numbers they are and .
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