Question

The sum of 5 consecutive integers is 505.

Answer 1

The sum of 5 consecutive integers is 505.

using algebra:

n+(n+1)+(n+2)+(n+3)+(n+4)=505

5n+10=505

5n=505-10

5n=495

n=495/5

n=99

n+1=100

n+2=101

Your answer

HOPE IT HELPS!! ☺️✌️☺️

Answer 2

Answer: 99,100,101,102,103

Step-by-step explanation:

The sum of 5 consecutive integers will be 5 times the middle number

So middle number is 505/5=101

So the numbers are 99,100,101,102 and 103