Question

The sum of 5 consecutive integers is 505 what is the third number in this sequence

Answer 1

using algebra:

n+(n+1)+(n+2)+(n+3)+(n+4)=505

5n+10=505

5n=505-10

5n=495

n=495/5

n=99

n+1=100

n+2=101 answer

using simple arithmetic:

505/5 gives the mean of the numbers and also the middle number which is the third number that you want

505/5=101

Answer 2

Answer:

using algebra:

n+(n+1)+(n+2)+(n+3)+(n+4)=505

5n+10=505

5n=505-10

5n=495

n=495/5

n=99

n+1=100

n+2=101 answer

Step-by-step explanation:

I hope it help you