History, asked by shifaalam, 3 months ago

The sum of 5 consecutive integers is 505 what is the third number in this sequenceI

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Answers

Answered by kindacutebabe
1

Answer:

101

Explanation:

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Answered by dhruv958champion88
1

i) We know d=1 cause numbers are consecutive

ii) Sn = n/2(2a+(n-1)d)

iii)505 = 5/2( 2a + (5-1)(1))

iv) 101x2 = 2a+4

v) 202 = 2a+4

vi) 101 = a+2

vii) a = 101-2

Therefore a = 99

The answer is still not complete

a is the first term

which implies third term will be a+3 = 102

Here is your answer

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