The sum of 5 consecutive integers is 505 what is the third number in this sequenceI
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1
Answer:
101
Explanation:
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Answered by
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i) We know d=1 cause numbers are consecutive
ii) Sn = n/2(2a+(n-1)d)
iii)505 = 5/2( 2a + (5-1)(1))
iv) 101x2 = 2a+4
v) 202 = 2a+4
vi) 101 = a+2
vii) a = 101-2
Therefore a = 99
The answer is still not complete
a is the first term
which implies third term will be a+3 = 102
Here is your answer
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