The sum of 5 consecutive integers is 75 find the smallest of these number
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They are centered around 75, so without doing any algebra we can say the numbers are 73, 74, 75, 76, 77; the least and greatest numbers are 73 and 77
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Let the common multiple be x
So, let the five consecutive integers be x, x + 1, x + 2, x + 3 and x + 4
Their sum is 75
According to the given condition
x + x + 1 + x + 2 + x + 3 + x + 4 = 75
Add the like terms
☛ 5x + 10 = 75
Move constant +10 to RHS
☛ 5x = 75 - 10
Subtract
☛ 5x = 65
Divide both the sides by 5
∴ x = 13
∴ The smallest number ☛ x
☛
So, let the five consecutive integers be x, x + 1, x + 2, x + 3 and x + 4
Their sum is 75
According to the given condition
x + x + 1 + x + 2 + x + 3 + x + 4 = 75
Add the like terms
☛ 5x + 10 = 75
Move constant +10 to RHS
☛ 5x = 75 - 10
Subtract
☛ 5x = 65
Divide both the sides by 5
∴ x = 13
∴ The smallest number ☛ x
☛
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