The sum of 5 consecutive numbers is 140 .find the numbers
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let no be x =5x=140
x=140/5=28
x=140/5=28
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Hi ,
x , ( x + 1 ) , (x+2),(x+3),(x+4) are
four consecutive numbers.
according to the problem given,
Their sum = 140
x + (x+1)+(x+2)+(x+3)+(x+4)=140
5x + 10 = 140
5x = 140 - 10
5x = 130
x = 130/5
x = 26
Therefore ,
Required 5 consecutive numbers are
x = 26
x + 1 = 26 + 1 = 27
x + 2 = 26 + 2 = 28
x + 3 = 26 + 3 = 29
and
x + 4 = 26 + 4 = 30
I hope this helps you.
: )
x , ( x + 1 ) , (x+2),(x+3),(x+4) are
four consecutive numbers.
according to the problem given,
Their sum = 140
x + (x+1)+(x+2)+(x+3)+(x+4)=140
5x + 10 = 140
5x = 140 - 10
5x = 130
x = 130/5
x = 26
Therefore ,
Required 5 consecutive numbers are
x = 26
x + 1 = 26 + 1 = 27
x + 2 = 26 + 2 = 28
x + 3 = 26 + 3 = 29
and
x + 4 = 26 + 4 = 30
I hope this helps you.
: )
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