Question

the sum of 5 numbers is 90 what is the digit in the units place of the maximum product of these 5 numbers?​

Answer 1

Given: The sum of 5 numbers is 90.

To maximize the product of the five numbers.

$50+10+10+10+10=90$

Therefore to maximize the product. The digits in the unit's place will be zero.

Answer 2

Given sum of five numbers is $90.$

Let the five numbers be $a, b, c, d, e$.

Maximum product of n numbers when sum $S$ is given is

$= (S/n)^n$  

$= (90/5)^5\\ = (18)^5$

Units place of $18^5$ is $8$

Therefore, units place of the maximum product of five numbers, when their sum is $90$ is $8$.