Question

the sum of 5 numbers is 924.the average of first two numbers is 201.5 and the average of last two numbers is 196. what is the third number?​

Answer 1

Answer:

answer is 129

Step-by-step explanation:

let those numbers are X,Y,Z,A,B x+y+z+a+b=924,x+y/2=201.5,x+y=403,a+b=196×2=392,403+392+z=924;z=129

Answer 2

Answer:

129

Step-by-step explanation:

Average of first two no. s = 201.5

sum of first two no.s /2 = 201.5

sum of first two no.s =201.5 x 2 = 403

similarly,

Average of last ywo no.s = 196

sum of last two no.s =196 x 2 = 392

Let the third no. be a .

We know,

sum of all the no.s = 924

403 + 392 + a =924

795 +a = 924

a = 924-795 = 129 . ans. ❤️