the sum of 5 th term and 7 th term of an AP is 52 and 10 th term is 46 .find the AP .
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Given:the sum of 5th and 7th term of a AP =52
An=a+(n-1)d
A5=a+(5-1)d
5th term=a+4d......................1
Similarly a+6d......................2
Solving eqn.. 1 and...2
( a+4d)+(a+6d)=56
a+46+a+6d=52
2a+10d=52...................................3
Taking 2 as common in eqn 3 we get
2 (a+5d)=52
2a+5d=52/2
a+56=26.......................................4
Now given 10th term =46
That is,10th term =a+9d=46,...........................5solving eqn ...4and...........5 we get
a+9d=46
a+5d=26
On subtraction
a+9d=46
-a-5d=-26
a gets cancel
We get..
4d=20
d=20/4
d=5
So i hope u understood
Actually i explained clearly as much i can
And frm this u can get the AP
All the best
An=a+(n-1)d
A5=a+(5-1)d
5th term=a+4d......................1
Similarly a+6d......................2
Solving eqn.. 1 and...2
( a+4d)+(a+6d)=56
a+46+a+6d=52
2a+10d=52...................................3
Taking 2 as common in eqn 3 we get
2 (a+5d)=52
2a+5d=52/2
a+56=26.......................................4
Now given 10th term =46
That is,10th term =a+9d=46,...........................5solving eqn ...4and...........5 we get
a+9d=46
a+5d=26
On subtraction
a+9d=46
-a-5d=-26
a gets cancel
We get..
4d=20
d=20/4
d=5
So i hope u understood
Actually i explained clearly as much i can
And frm this u can get the AP
All the best
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