Question

the sum of 50 observation is 500, its sum of square is 6000 and median 12.find the cofficient of skewness​

Answer 1

Answer:

Given, ∑(x−xˉ)^2=250,n=10,xˉ=50

Thus standard deviation =n∑(x−xˉ)^2=25

=5

∴ Coefficient of variation =xˉσ×100=5/50×100 % =10%

Step-by-step explanation:

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Answer 2

Answer:

Coefficient of skewness = - 1.3

Step-by-step explanation:

Given data

sum of the 50 observations = 500

sum of the squares               = 6000

                             median     =  12  

The formula for coefficient of skewness = $\frac{3 (mean - median) }{S.D}$  

here S.D = standard deviation

here we need to calculate mean and S.D to calculate coefficient of skewness

from given data  mean of 50 observations

                      =  sum of the observation/ number of observations

                      =  500/ 50 =  10  

standard deviation (S.D) =  √[∑x²/N - (mean)²]  

                                        = √[ 6000/50 - (10)²]  

                                        = √[ 120 -100]  = √20  

                                        = √(4×5) = 2(2.23) = 4.6        [ $\sqrt{5}$ taken as 2.23]    

coefficient of skewness = $\frac{3(mean - median )}{S.D}$

                                        = $\frac{3(10 - 12)}{4.6}$  = $\frac{3(-2)}{4.6}$  =  -6/4.6 = $- 1.3$