Question

The sum of 55 consecutive integers is 505.
What is the third number in this sequence

Answer 1

Answer:

The answer is 101

Hope it helped you.

Answer 2

Sum of n numbers =S = (n/2) [ 2a + (n-1)d]

S = 505

n= 55

d = 1 (all the numbers are consecutive)

Putting all the values in formula we get

505 = (55/2) [ 2a + (55-1)1]

505 = (55/2) [ 2a + 54]

505/55 = a + 27

505/55 = a + 27

(101/11) -27 = a

a = 398/11

3rd term will be

a+2 = (398/11) + 2 = 420/11 = 38.18