Question

The sum of 55 consecutive odd numbers is 145

Answer 1

Let the first odd number be n.

The 4 consecutive odd numbers should be:

n+2, n+4, n+6 and n+8.

The sum of these 5 consecutive odd numbers should be 145. Therefore, if we add them up:

n+(n+2)+(n+4)+(n+6)+(n+8) = 145

5n + 20 = 145

n = 25

Therefore the five consecutive odd numbers are: 25, 27, 29, 31, 33

Answer 2

Answer:

25

Step-by-step explanation:

I think the question is the sum of 5 consecutive odd numbers is 145. So assuming let the odd number be n and the next numbers will follow as        n + 2, n + 4, n + 6, n + 8. They have mentioned as sum, so adding we have

 n + n + 2 + n + 4 + n + 6 + n + 8 = 145

   5 n + 20 = 145

  5 n = 145 - 20

 5 n = 125 or

  n = 125 / 5

  n = 25