Question

The sum of 5th term & 7th term of an AP is 52 & 10th term is 46. Find the AP. WRITE THE SOLUTION AND SEND ME .​

Answer 1

Answer:

a5 + a7 = 52

we can write this as

a +4d + a+6d = 52

=> 2a +10d = 52

=> a+ 5d = 26.....(1)

also a10 = 46

which can be written as

a+9d = 46......(2)

subtracting 1 from 2

a+9d-(a+5d)= 46-26

a+9d-a-5d=20

4d = 20

d= 5

putting it's value in eq.2

a+ 9(5)= 46

=> a= 46-45

=>a = 1

so a = 1

a1= 1+5 =6

a2= 6+5 = 11

a3= 11+5= 16

so the ap is 1,6,11,16....

Step-by-step explanation:

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Answer 2

Answer:

a5=a+4d-------------(1)

a7=a+6d-------------(2)

so,a5+a7=a+4d+a+6d=52 (given)

= 2a+10d=52

= a+5d=26-------------(3)

and,a10=a+9d=46 (given)------------(4)

Now ,subtracting equation 3 from 4,

we get,

a+5d-(a+9d)=26-46

a+5d-a-9d=26-46

-4d= -20

d=5------------------(i)

put this in eq (3);

a+5d=26

a+5(5)=26

a+25=26

we get, a=1

Now,

A.P;

1,6,11,16,21,26........