Question

The sum of 6 consecutive integers is 393. what is the third number in the sequence?

Answer 1

let the six consecutive nos be x, x+1, x+2, x+3, x+4, x+5
according to the question
x+x+1+x+2+x+3+x+4+x+5 =393
6x +15 =393
6x = 393 - 15
x = 378 / 6
x = 63

.: the third no is = 63+2
=65

Answer 2

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