The sum of 6 tems of an arithmetic progression is 345.the difference between the first and last term is 55 find the 6 terms
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S6=345
a - (a+5d)=55
a-a-5d=55
d=-11
S6=6/2[2a+5.-11]
345=3(2a-55)
115=2a-55
2a=170
a=85
a6=a+5d
a6 =85-55
a6=30
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