Question

- The sum of 6 terms form an A.P. is 345. The difference of the first and the last terms is 55. Find the six terms of the A.P.​

Answer 1

Step-by-step explanation:

6/2(2a+(6-1)d)=345

3(2a+5d)=345

2a+5d=115

a+5d-a=55

5d=55

d=5

2a+25=115

2a=90

a=45

Therefore the required AP=45,50,55,60,65,70...