the sum of 6 terms which form an AP is 345. the difference between the first and the last term is 55 find the terms
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Step-by-step explanation:
sum of 6 term= 345
n/2[2a+(n-1) d] =345
6/2 [2a + (6-1)d]=345
3(2a + 5d) = 345
2a+5d = 345/3
2a+5d=115 =1.)
difference of 1st and nth term= n-a = 55
a+(n-1)d-a = 55
(n-1)d =55
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