Question

the sum of 6 terms which form an AP is 345. the difference between the first and the last term is 55 find the terms​

Answer 1

Answer:

Step-by-step explanation:

sum of 6 term= 345

n/2[2a+(n-1) d] =345

6/2 [2a + (6-1)d]=345

3(2a + 5d) = 345

2a+5d = 345/3

2a+5d=115 =1.)

difference of 1st and nth term= n-a = 55

a+(n-1)d-a = 55

(n-1)d =55