Question

The sum of 66 consecutive integers is 519

Answer 1

Answer:

Step-by-step explanation:

let x be the first integer, then

:

x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519

:

6x + 15 = 519

:

6x = 504

:

x = 84