Question

The sum of 68 consecutive integers m,m+1 what is the sum of their squares

Answer 1

is the question correct?

Answer 2

Answer: Sum of their squares is 2312.5.

Step-by-step explanation:

Since we have given that

Let the two consecutive integers be m, m+1.

Sum of two consecutive integers = 68

According to question, it becomes,

$m+m+1=68\\\\2m+1=68\\\\2m=68-1\\\\2m=67\\\\m=\dfrac{67}{2}\\\\m=33.5$

So, sum of their squares would be

$(33.5)^2+(34.5)^2=2312.5$

Hence, sum of their squares is 2312.5.