Math, asked by sparsh7113, 7 months ago

The sum of ( 6a + 4b - c + 3 ), ( 2b - 3c + 4 ), ( 11b - 7a + 2c - 1 ) and ( 2c - 5a -6 ) is

Answers

Answered by shubhangiii
6

Answer:

-6a + 19b

Step-by-step explanation:

Adding terms with same variable.

( 6a + 4b - c + 3 ) + ( 2b - 3c + 4 ) + ( 11b - 7a + 2c - 1 ) + ( 2c - 5a -6 )

=> ( 6a - 7a - 5 a ) + ( 4b +2b +11b ) + ( -c -3c + 2c + 2c ) + ( 3 + 4 -1 - 6 )

=> -6a + 19b + 0c + 0

=> -6a + 19b

Answered by VarunGuleria
3

Answer:

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