Question

The sum of ( 6a  + 4b - c + 3 ) , ( 2b - 3c + 4 ) , ( 11b - 7a + 2c - 1 )  and  ( 2c - 5a - 6 ) is   


 (a)    ( 4a - 6b + 2 )          (b)  ( - 3a + 14b - 3c + 2 )     (c)  ( - 6a  + 17b )        (d)    ( -6a  + 6b + c - 4 )

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Answer 1

Step-by-step explanation:

The sum of ( 6a  + 4b - c + 3 ) , ( 2b - 3c + 4 ) , ( 11b - 7a + 2c - 1 )  and  ( 2c - 5a - 6 ) is   

(c)  ( - 6a  + 17b ) 

Answer 2

Answer:

option number (c) is correct

Step-by-step explanation:

6a+4b -c. + 3. 0 +2b-3c +4. -7a+11b+2c -1. -5a+0. +2c -6. ---------------------- -6a + 17 b + 0 +0. ------------------------ THANKS YOU