The sum of ( 6a + 4b - c + 3),( 2c - 5a - 6 ),( 2b - 3c + 4 ) and ( 11b - 7a + 2c - 1 ) is ?
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22
Step-by-step explanation:
6a+4b-c+3+2c-5a-6+2b-3c+4+11b-7a+2c-1
-6a+17b-2c+2c+1-1
-6a+17b
6a-17b
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Answered by
5
Answer:
the right answer is -6a+17b
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