The sum of 6th and 10th term of an ap is 66. Find The sum of first 15th term of this sequence
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The 4^th term of A.P. is 22...
MATHS
The 4
th
term of A.P. is 22 and 15
th
term is 66. Find the first term and the common difference. Hence find the sum of the series to 8 terms.
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ANSWER
Let a be the first term and d be the common difference of the A.P.
Now, 4
th
term of the A.P. = a+3d=22 ... (1)
Also, 15
th
term of the A.P. = a+14d=66 ... (2)
Subtracting (1) from (2), we get
11d=44⟹d=4
Substituting value of d in (1), we have
a+12=22⟹a=10
Sum of first 8 terms =
2
n
(2a+(n−1)d)=
2
8
(20+(8−1)4)=192
Hence, the first term, the common difference and the sum upto 8 terms are 10,4 and 192 respectively.
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