Question

The sum of 7 consecutive natural numbers is 70.what are the number

Answer 1

$\huge{\bf{\mathtt{\green{aNsWeR}}}}$

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→ $\large{\mathtt{\bf{\red{GivEn}}}}$

• 7 consecutive numbers

• sum = 70

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→ $\large{\bf{\mathtt{\red{ToFinD}}}}$

• 7 consecutive numbers

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→ $\large{\bf{\mathtt{\red{ConSeDeRinG}}}}$

• 1st no - x

• 2nd no - x + 1

• 3rd no - x + 2

• 4th no - x + 3

• 5th no - x + 4

• 6th no - x + 5

• 7th no - x + 6

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$\large{\bf{\mathtt{\red{SoLuTioN}}}}$

• x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 + x + 6 = 70

• 7x + 21 = 70

• 7x = 70 - 21

• 7x = 49

• x = $\large{\bf{\cancel{\frac{49}{7}}}$

• $\large{\bf{\red{\boxed{\boxed{X\:=\:7}}}}}$

hence ,

➜ 1st no = x = 7

➜ 2nd no = x + 1 = 7 + 1 = 8

➜ 3rd no = x + 2 = 7 + 2 = 9

➜ 4th no = x + 3 = 7 + 3 = 10

➜ 5th no = x + 4 = 7 + 4 = 11

➜ 6th no = x + 5 = 7 + 5 = 12

➜ 7th no = x + 6 = 7 + 6 = 13

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Answer 2

Answer:

Hope it helps dear..................