Question

the sum of 7 number is 56 and the sum of their square is 611

Answer 1

Step-by-step explanation:

Let the smaller number be x.

Hence the other number will be 18−x

Hence, from the given condition,

x(18−x)=56

18x−x

2

=56

∴x

2

−18x+56=0

x

2

−14x−4x+56=0

x(x−14)−4(x−14)=0

(x−4)(x−14)=0

∴x=4,14

∴ two numbers are 4,14