Question

The sum of a 2 digit no and no obtained by reversing the odet of digit is 99

Answer 1

Case 1:

Let the digit at ones place = y

And the digit at the tens place = x

Then the original number = 10x+y

After reversing, the new number = 10y+x

According to the question,

10x+y+10y+x = 99

11x+11y = 99

Case 2:

Let the digit at ones place = x

And the digit at the tens place = y

Then the original number = 10y+x

After reversing, the new number = 10x+y

According to the question,

10x+y+10y+x = 99

11x+11y = 99

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