Question

The sum of a 2 digit no. and no. obtained by reversing the order of digits is 99. if the digits of the the no. differ by 3 . find the no.

Answer 1

let the 2 nos be
tens place=x ones place=y
the no is 10x+y
reversed no=10y+x

ATQ,
x-y=3 .........(i)

given,
(10x+y)+(10y+x)=99
11x+11y=99
x+y=9........(ii)

eq(i) - eq(ii)
x-y=3
x+y=9
2x=12
x=6
y=3

hence, no. is 36....
hope this will help.