Question

The sum of a 2 - digit number and the number formed by reversing the digits is 33. Also the sum of digits is 4. Find the number ​

Answer 1

EXPLANATION.

Let the number at ten's place be = x

Let the number at unit place be = y

original number = 10x + y

reversing number = 10y + x

To find the number.

According to the question,

The sum of a two digit number and the

number formed by reversing the digit = 33

=> 10x + y + 10y + x = 33

=> 11x + 11y = 33

=> x + y = 3 .........(1)

The sum of two digit number = 4

=> x + y = 4 .......(2)

From equation (1) and (2) we get,

=> X = 0 and y = 0

Therefore,

Original number = 10x + y = 10(0) + 0 = 0

Answer 2

Answer:

let the number be 10x + y. ATQ,

Step-by-step explanation:

10x + y + 10y + x = 33

x + y = 4

11(x + y) = 33

x + y = 4

x + y = 3

x + y = 4

This is an impossible equation, so there's no such 2-digit number in which if reversed, the sum is 33.