. The sum of a 2-digit number and the number formed by reversing its digits is exactly divisible by 11, and the quotient is the sum of the digits of the original 2-digit number. Does this hold true for all 2-digit numbers? Prove it.
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Step-by-step explanation:
Divide the answer by 11. Result: There is no remainder. Remark: The sum of a two-digit number and the number formed by reversing its digits is exactly divisible by 11 and the quotient obtained is the sum of the digits of the original 2-digit number. ∴ Hence proved.
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