The sum of a 2 digit number and the number obtained by reversing the order of its digit is 165 . If the digit differ by 3 find the number
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Let the number=10x+y
Reversing the order=10y+x
So,
10x+y+10y+x=165
11x+11y=165
x+y=165/11
x+y=15
x-y=3
2x=18
x=9
x+y=15
y=6
Now,
the number is 10x+y
=10(9)+6
=96
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