The sum of a 2 digit number is 11. If the number obtained by reversing the digit is 9 less than the original number, what is the number?
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The sum of a 2 digit number is 11. If the number obtained by reversing the digit is 9 less than the original number, what is the number?
let the number be 10x + y
- x + y = 11
- 10x + y = 9 + 10y + x
- the correct number
x + y = 11 -------------(i)
10x + y = 9 + 10y + x
10x - x + y -10y = 9
9x - 9y = 9
9(x-y)= 9
x-y = 1-----------(ii)
- adding eq (i) and (ii)
x + y + x - y = 11 + 1
2x = 12
x = 6
- putting value of x in eq (i)
x+y = 11
6+y = 11
y = 11-6
y = 5
required no. = 10x + y = 10 * 6 + 5 = 60 + 5 = 65
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Answered by
50
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- The sum of a 2 digit number is 11. If the number obtained by reversing the digit is 9 less than the original number, what is the number?
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- The number is 65.
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- The number according to the question.
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- Sum of a 2 digit number is 11.
- The no. obtained by reversing the digit is 9 less than the original no.
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- Let the 2 digit number be
- Number obtained by reversing the digit be
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