the sum of a 2-digit number is 13. If the number obtained by interchanging the digits exceeds the original by 27, find the number.
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Let the ones digit of no. be x
then the tens digit will be y
then x+10y = 13
10y = 13-x
then the tens digit will be y
then x+10y = 13
10y = 13-x
MPP:
this not right.
i want to know what is the number in tens place and ones place.
pls change
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