Question

the sum of a 2 digit number is 9 and its tens digit is 5 more than the unit digit find the no.

Answer 1

Answer:

36

Step-by-step explanation:

Answer

Let the digits at tens place and ones place: x and 9−x respectively.

∴ original number =10x+(9−x)

=9x+9

Now Interchange the digits: Digit at ones place and tens place: x and 9−x respectively.

∴ New number: 10(9−x)+x

=90−10x+x

=90−9x

AS per the question

New number = Original number +27

90−9x=9x+9+27

90−9x=9x+36

18x=54

x=  

18

54

​  

 

x=3

Digit at tens place ⇒3 and one's place : 6

∴ Two digit number: 36

Answer 2

Answer:

72

Step-by-step explanation:

let unit digit be x

Tens digit = x+5

x+5+x  = 9

2x = 4

x = 2

Hence the no is 72