Question

the sum of a digit nimber and number obtain by reversing the digit is 66 if the digit of the number differ. by 2 find the number how much such numbers are there?

Answer 1

6+60=66 answer= 6....

Answer 2

Hello here is your answer by Sujeet yaduvanshi ____________________________________________________________________________________________________________________________________________________________________________________




Question:-)the sum of two digit nimber and number obtain by reversing the digit is 66 if the digit of the number differ. by 2 find the number how much such numbers are there?

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Solution:-

Let to be 10' unit digit number be x


Let to be 1 unit digit number y


then,.

Original number=10x+y

Required Number=10y+x

According to the question...

10x+y+10y+x=66

11x+11y=66

11(x+y)=66

x+y=66/11

x+y=6. (First Equation)



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Again.......


x-y=2



Solving the equation...

x+y=6
x-y=2



By Elimination method for solving this question....



x+y=6
x-y=2

________
2y=4

y=4/2

y=2

Putting the value of y in another equation


x+y=6

x+2=6

x=6-2

x=4




Required Number be. 10x+y

10*4+2

40+2


42


that's all


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SUJEET KUMAR YADUVANSHI