Question

the sum of a digit of a two digit number is 7 if the digits are reversed the new number increased by 3 less than the four times the original number find the original number
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Answer 1

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Answer 2

16, 61

1 + 6 = 7

61 = 4(16) - 3

Let’s set original number at (10x +y) and the reversed digit number as (10y + x).

It has already been defined that x + y = 7.

The reversed digit number will be (4 * (original number)) - 3

10y + x = 4(10x + y) -3

Solve for y.

y = -1/2 + (13/2)x

Plug into x + y = 7, and solve for x.

x = 1

Therefore, y = 6

1 + 6 = 7

10(6) + 1 = 4(10(1) +6) - 3

61 = 40 + 24 - 3

61 = 61
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