The sum of a digit of a two digit number is 9. the digit at tens place is 4 less than 1/6th of the number. find the number
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Let the tens digit be x
Let the ones digit be y
x + y = 9
y = 9-x
Number = (10x+y)
1/6th of number = (10x+y)/6
(10x+y)/6 - x = 4
(10x+9-x)/6 - x = 4
(9x+9-6x)/6 = 4
3x+9 = 24
3x = 15
x=5
y= 9-x = 9-5 = 4
The number = 10x+y = 10*5+4 = 54
Let the ones digit be y
x + y = 9
y = 9-x
Number = (10x+y)
1/6th of number = (10x+y)/6
(10x+y)/6 - x = 4
(10x+9-x)/6 - x = 4
(9x+9-6x)/6 = 4
3x+9 = 24
3x = 15
x=5
y= 9-x = 9-5 = 4
The number = 10x+y = 10*5+4 = 54
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