Question

The sum of a digit of two digit number is 9. The digit in the ones place is 1 metre more than 3 times the digit in the tens place. Find the number

Answer 1

Answer:

Let ones place digit be x

Therefore digit at tens place will be, = 1/2*x

Sum of digits=9So,eq-

X+x/2=9

3x/2=9

x=9*2/3=6

Number=36

Answer 2

Answer:

Let the digits at tens place and ones place: x and 9−x respectively.

∴ original number =10x+(9−x)

= 9x+9

Now Interchange the digits: Digit at ones place and tens place: x and 9−x respectively.

∴ New number:

10(9−x)+x

= 90−10x+x

= 90−9x

AS per the question

New number = Original number +27

90−9x=9x+9+27

90−9x=9x+36

18x = 54

x= 54 / 18

• x = 3

Digit at tens place ⇒3 and one's place : 6

∴ Two digit number: 36