the sum of a digits of a 2 digit no. is 11.if 9is adde to the number its digits are reversed. find the number.
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Answered by
1
Answer:
let the digit at unit place be X
then, the digit at the tens place=11-x
original number=10(11-x)+1*X
=110-10x+X
=110-9x
digit obtained by reversing its digit
=10*X+1(11-x)
=10x+11-x
=9x+11
A/Q
110-9x+9=9x+11
=119-9x=9x+11
=119-11=9x+9x
=108=18x
=108/18=X
=6=X
original number=110-9x
=110-9*6
=110-54
=56
Answered by
1
Step-by-step explanation:
the tens digit b x .
the unit digit b 11-x
original no. 10×x+11-x
......10x-x+11
9x+11
when the no. reversed
the tens digit 11-x
unit digit x
reversed no. 10×{11-x}+x
110-10x+x
110-9x
ATQ=
9x+11+9=110-9x
then u solve this equation
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