Question

The sum of a digits of a two digit number is 17 and the difference between the digits is 1 . What is that two digit number?

Answer 1

Answer:

x-y=1

x-1=y

So if x+y=17

It means that

x+(x-1)=17

x+x-1=17

2x-1=17

2x=17+1

2x=18

X=18÷2

X=9

The sum is 17

So the other number is 17-9=8

So the answer is 8and 9

Step-by-step explanation:

Answer 2

The required number is 98

Given:

The sum of a digits of a two digit number is 17

The difference between the digits is 1

To find:

The two digit number

Solution:

Let A be the number in tens place and B be the number in ones place

Then the required number =  10A+B

Given that Sum of two digits = 17

⇒ A+B = 17 -----(1)

The difference between the digits is 1  

⇒  A-B = 1 ------(2)

Now add (1) and (2)

⇒  A + B + A-B  = 17 +1

⇒ 2A = 18

⇒ A = 9

Now substitute A = 9 in (1)

⇒ 9+B = 17

⇒ B = 8

Therefore, the required number,  10A+B = 10(9) +8 = 98

The required number is 98

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