the sum of a natural number and is reciprocal is 37÷6.what is the number
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let x be the natural number
then according to question
x+(1/x)=37/6
=>x^2+1/x=37/6
=>x^2+1=37x/6
=>x^2-(37x/6)+1=0
multiplying by 6 we get
=>6(x^2)-37x+6=0
solving this by the formula
as 1/12 is not a natural no..we will take 6 which is the appropriate answer as the required one
then according to question
x+(1/x)=37/6
=>x^2+1/x=37/6
=>x^2+1=37x/6
=>x^2-(37x/6)+1=0
multiplying by 6 we get
=>6(x^2)-37x+6=0
solving this by the formula
as 1/12 is not a natural no..we will take 6 which is the appropriate answer as the required one
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