The sum of a natural number and it's reciprocal is 65/8 . Find the number .
Samigupta70766:
answer is 8
Answers
Answered by
72
let required no. be x
and, reciprocal be 1/x.
according to question,
x + 1/x = 65/8
x^2 + 1/ x = 65/8
8x^2 - 65x + 8 = 0
8x^2 - 64x - x +8 =0
8x(x-8) -1(x-8)=0
(8x-1) (x-8)=0
thus, the no. can be either 1/8 or 8.
and, reciprocal be 1/x.
according to question,
x + 1/x = 65/8
x^2 + 1/ x = 65/8
8x^2 - 65x + 8 = 0
8x^2 - 64x - x +8 =0
8x(x-8) -1(x-8)=0
(8x-1) (x-8)=0
thus, the no. can be either 1/8 or 8.
Answered by
8
Answer:
let the number is x . so , x +1/x =65/8 . and the equation formed is 8xsquare - 65 x + 8 =0 . and when we solve it by the quadratic formula we get the answer that is 8.
Step-by-step explanation:
let the number is x . so , x +1/x =65/8 . and the equation formed is 8xsquare - 65 x + 8 =0 . and when we solve it by the quadratic formula we get the answer that is 8.
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