Question

the sum of a natural number and it's square is 42 find the number?​

Answer 1

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Let the number be x.

ATQ,

x² + x = 42

x² + x - 42 = 0

x² + 7x - 6x - 42 = 0

x(x+ 7) -6(x+7)

(x - 6)(x + 7)

x = 6 , -7