The sum of a natural number and its positive square root is 132.find the number
quadratic equation class 10
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Answered by
1
Answer:
11 or -12
Step-by-step explanation:
Let the natural no be = x²
Let its square be = x
Then,
=> x²+x=132
=x²+x-132=0
=x²+(12-11)x-11x12=0
=x²+12x-11x-132=0
=x(x+12)-11(x+12)=0
=(x-11)(x+12)
=x=11
Or x=-12
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4
Answer:
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