the sum of a natural number and its positive square root is 132. find the number.
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Answered by
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Step-by-step explanation:
the number is 121
121 + √121 = 132
Answered by
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Answer:
n + √n = 132
=> let the value of √n = x
=> so the equation is x^2 + x = 132
x^2 + x -132= 0
x ^2 + 12 x -11 x -132 =0
=> x ( x + 12 ) - 11 ( x + 12) = 0
=> (x + 12 ) ( x -11 )
=> x = -12 , x = 11
so we can not take the value of x in negative
x = 11
proof.
11^2 + √121 = 132
hope it will help you..
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