Question

the sum of a no and its positive square root is 6/25​

Answer 1

Let the no. be x

x+√x=6/25

x=1/25

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Answer 2

Let the unknown number be x.

According to the question,

${x}^{2} + x = \frac{6}{25} \\ \\ \implies 25 {x}^{2} + 25x - 6 = 0 \\ \\ \implies 25 {x}^{2} + 30x - 5x - 6 = 0 \\ \\ \implies 5x(5x + 6) - 1(5x + 6) = 0 \\ \\ \implies (5x + 6)(5x - 1) = 0 \\ \\ \boxed{x = \frac{ - 6}{5} \: or \: x = \frac{1}{5} }$

But x cannot be negative so x = 1/5

Therefore the no. is ,

${ (\frac{1}{5}) }^{2} = \frac{1}{25}$